---
description: 'Enforce specifying generic type arguments on type annotation or constructor name of a constructor call.'
---

> 🛑 This file is source code, not the primary documentation location! 🛑
>
> See **https://typescript-eslint.io/rules/consistent-generic-constructors** for documentation.

When constructing a generic class, you can specify the type arguments on either the left-hand side (as a type annotation) or the right-hand side (as part of the constructor call):

```ts
// Left-hand side
const map: Map<string, number> = new Map();

// Right-hand side
const map = new Map<string, number>();
```

This rule ensures that type arguments appear consistently on one side of the declaration.

## Rule Details

The rule never reports when there are type parameters on both sides, or neither sides of the declaration. It also doesn't report if the names of the type annotation and the constructor don't match.

## Options

- `constructor` _(default)_: type arguments that **only** appear on the type annotation are disallowed.
- `type-annotation`: type arguments that **only** appear on the constructor are disallowed.

### `constructor`

<!--tabs-->

#### ❌ Incorrect

```ts
const map: Map<string, number> = new Map();
const set: Set<string> = new Set();
```

#### ✅ Correct

```ts
const map = new Map<string, number>();
const map: Map<string, number> = new MyMap();
const set = new Set<string>();
const set = new Set();
const set: Set<string> = new Set<string>();
```

### `type-annotation`

<!--tabs-->

#### ❌ Incorrect

```ts
const map = new Map<string, number>();
const set = new Set<string>();
```

#### ✅ Correct

```ts
const map: Map<string, number> = new Map();
const set: Set<string> = new Set();
const set = new Set();
const set: Set<string> = new Set<string>();
```

## When Not To Use It

You can turn this rule off if you don't want to enforce one kind of generic constructor style over the other.
